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Question about buff duration - Durationformula

Hi folks,

I have been trying to determine what is actually behind the "Durationformula" for spells to calculate the duration for levels 1-65. For some spells, it's pretty simple, for example:

- Ensnare: Buff Duration: 140 (14.0 minutes), Durationformula: "Level * 2 + 10" (durationformula 9).

With the above it's simple to figure out the spell duration for Ensnare at any character level.

However, with this spell, as an example:

- Snare: Buff Duration: 39 (3.9 minutes), Durationformula: "Duration * 3/5" (durationformula 2).

It's not easy (well, for me) to use this Durationformula and others to calculate duration by level.

I was hoping someone could shed some light into what "Duration * 3/5", "Duration / 2" etc. actually mean for determining the duration for the spells with those formulas at say, level 14, or whatever.

Thanks in advance.

Code:

// the generic formula calculations

int CalcBuffDuration_formula(int level, int formula, int duration)

{

        int i;        // temp variable



        switch(formula)

        {

                case 0:        // not a buff

                        return 0;



                case 1:

                        i = (int)ceil(level / 2.0f);

                        return i < duration ? (i < 1 ? 1 : i) : duration;



                case 2:

                        i = (int)ceil(duration / 5.0f * 3);

                        return i < duration ? (i < 1 ? 1 : i) : duration;



                case 3:

                        i = level * 30;

                        return i < duration ? (i < 1 ? 1 : i) : duration;



                case 4:        // only used by 'LowerElement'

                        return ((duration != 0) ? duration : 50);



                case 5:

                        i = duration;

                        // 0 value results in a 3 tick spell, else its between 1-3 ticks.

                        return i < 3 ? (i < 1 ? 3 : i) : 3;



                case 6:

                        i = (int)ceil(level / 2.0f);

                        return i < duration ? (i < 1 ? 1 : i) : duration;



                case 7:

                        i = level;

                        return (duration == 0) ? (i < 1 ? 1 : i) : duration;



                case 8:

                        i = level + 10;

                        return i < duration ? (i < 1 ? 1 : i) : duration;



                case 9:

                        i = level * 2 + 10;

                        return i < duration ? (i < 1 ? 1 : i) : duration;



                case 10:

                        i = level * 3 + 10;

                        return i < duration ? (i < 1 ? 1 : i) : duration;



                case 11:

                        return duration;



                case 12:

                        return duration;



                case 15:        // Don't know what the real formula for this should be. Used by Skinspikes potion.

                        return duration;



                case 50:        // lucy says this is unlimited?

                        return 72000;        // 5 days



                case 3600:

                        return duration ? duration : 3600;



                default:

                        LogFile->write(EQEMuLog::Debug, "CalcBuffDuration_formula: unknown formula %d", formula);

                        return 0;

        }

}

Heres the code if you think the math will better explain it :p

Quote:

Originally Posted by NatedogEZ (Post 230896)

Heres the code if you think the math will better explain it :p

That could work, thank you!

Also take note... the duration it returns is in "ticks" of 6 seconds

so if it returns a duration of 60 -- that is 6 minutes :)

Quote:

Originally Posted by NatedogEZ (Post 230898)

Also take note... the duration it returns is in "ticks" of 6 seconds

so if it returns a duration of 60 -- that is 6 minutes :)

I took a look at the full spells.cpp just now and that's pretty well explained too

However case 2:

Code:

i = (int)ceil(duration / 5.0f * 3);

return i < duration ? (i < 1 ? 1 : i) : duration;

is still mystifying to me. How is character level taken into account here for these spells including the druid level 1 Snare that clearly scales with level? O_o

It takes the duration, which default for Snare is "39", divides it by a float 5.0 * 3, rounds it to the nearest int, and that is supposed to = duration. What?

The formula looks incorrect.. its supposed to scale with level.. but it does not :p

Pretty sure case 2: should be this.... (going from what is posted on Lucy for spells that have that formula ID)

Code:

i = (int)ceil(level * 0.6f);

return i < duration ? (i < 1 ? 1 : i) : duration;

http://lucy.allakhazam.com/spell.htm...42&source=Live

At level 1 -- it returns 1 tick
at level 65 it returns 39 ticks (or MAX duration)

formula works with this spell too ... so it seems to be right on :)

http://lucy.allakhazam.com/spell.htm...97&source=Live

Quote:

Originally Posted by NatedogEZ (Post 230901)

Pretty sure case 2: should be this.... (going from what is posted on Lucy for spells that have that formula ID)

Code:

i = (int)ceil(level * 0.6f);

return i < duration ? (i < 1 ? 1 : i) : duration;

http://lucy.allakhazam.com/spell.htm...42&source=Live

At level 1 -- it returns 1 tick
at level 65 it returns 39 ticks (or MAX duration)

Works for me. Thanks again! :)