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Old 10-31-2012, 12:10 PM
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c0ncrete
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Join Date: Dec 2009
Posts: 719
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i'm not familiar with the proper terminology, honestly. i've seen both and i guess i just chose the one that made the most sense in english to me.

regardless, i'm not really sure i understand your response. i'm trying to determine if i can forgo checking the value of group->members[i]->IsClient() and then checking for the value of group->members[i]->CastToClient()->AggroCount in a group with both bots and clients by adding the previous inline to the Client class, since group->members[i] is a pointer to a Mob. would it return the value of the new Client member without the explicit cast, or would it still be using IsEngaged() as defined in Mob?

thanks for the response.

Last edited by c0ncrete; 10-31-2012 at 12:10 PM.. Reason: corrected syntax
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