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Old 04-02-2013, 10:06 AM
vkrr
Sarnak
 
Join Date: Mar 2013
Posts: 65
Default

here's what I got so far
Code:
select * from items
where `Name` like 'FABLED%'
or `Name` in (
  select replace(`Name`, 'FABLED ', '') as fable_item
  from items
  where `Name` like 'FABLED%'
);
but now im stuck trying to manipulate the items. I think I took a wrong approach here... any help?
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